x^2+58x+216=0

Solution for x^2+58x+216=0 equation:

x^2+58x+216=0

a = 1; b = 58; c = +216;
Δ = b2-4ac
Δ = 582-4·1·216
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-50}{2*1}=\frac{-108}{2}
=-54
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+50}{2*1}=\frac{-8}{2}
=-4
$